A varies directly as x and B is inversely proportional to x^2. Given that y= A+B and that y= 19 when x=2 or 3, express y in terms of x.

Answer 1

A = mx
B = n/x^2

y = A+B = mx + n/x^2
19 = 2m + n/4
19 = 3m + n/9
m=5
n=36

y = 5x + 36/x^2

Answer 2

Thanks!