Asked by Chloe
The value of y varies directly with x. If y = 64 when x is 16, what is x when y is 288?
Answers
Answered by
Jai
y varies directly with x:
y = kx
where k is some constant. To find this k, substitute the given x and y:
64 = k(16)
k = 64/16
k = 4
To find x, substitute y = 288 and k = 4:
288 = 4x
Now solve for x.
Hope this helps :3
y = kx
where k is some constant. To find this k, substitute the given x and y:
64 = k(16)
k = 64/16
k = 4
To find x, substitute y = 288 and k = 4:
288 = 4x
Now solve for x.
Hope this helps :3
Answered by
Chloe
It did help. Thank you so much! cx
Answered by
Shiloh!
X=72
Answered by
Anonymous
x=72
Answered by
Zane from One Direction
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