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Asked by illiana

The average (mean) value of (1/x) over the interval 1<= x<= e is
a)1
b)(1/e)
c)(1/e^2)-1
d)(1+e)/2
e) 1/(e-1)
13 years ago

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Answered by drwls
(ln e - ln1)/(e-1) = 1/(e-1)
13 years ago
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The average (mean) value of (1/x) over the interval 1<= x<= e is
a)1
b)(1/e)
c)(1/e^2)-1
d)(1+e)/2
e) 1/(e-1)

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