Asked by melek
Find the solution of the exponential equation, correct to four decimal places.
4^(2x − 1) = 6
4^(2x − 1) = 6
Answers
Answered by
Steve
4^(2x-1) = 6
(2x-1) * log4 = log6
2x-1 = log6/log4
x = (log6/log4 + 1)/2
(2x-1) * log4 = log6
2x-1 = log6/log4
x = (log6/log4 + 1)/2
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