Find the solution of the exponential form in terms of logarithms

2^(2x+13) = 3^(x-45)

3 answers

(2x+13) log 2 = (x -45) log 3
2x(log2 + 13log2 = x(log3) - 45log3
2x(log2) - x(log3) = -45log3 - 13log2
x(2log2 - log3) = -45log3 - 13log2
x = (-45log3 - 13log2)/(2log2 - log3)
x = -203.17

4e^x=91

2lnx-2+lny+.25lny

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