Ask a New Question

Question

Determine the slope of the tangent to the curve y=2(x^2+x-1)^3 at (-1, -2)
13 years ago

Answers

Reiny
dy/dx= 6(x^2+x-1)^2 (2x+1)
at (-1,-2)

dy/dx= 6(1-1-1)^2 (-2+1)
= -6

so now you have the slope of -6 and a point(-1,-2)

continue ....
13 years ago
Jessi
So

y2-y1=m(x2-x1)

y-(-2)=-6(x-(-1)
y=6x-1

therefore the slope of tangent is 6?
13 years ago

Related Questions

Determine the slope of the tangent line to the curve y=2x^3-3x^2+1 at the point (1,0) Determine the slope of the tangent to the function f(x)=5xe^x at the point with x-coordinate x=2... Determine the slope of the tangent line to the curve y=(x^2+3x)(x^2-2) at x=-1. I got 3 as my ans... Determine the slope of the tangent to the function f(x)=5e^x - 2e^(2x) at the point with x-coordinat... Determine the slope of the tangent at the indicated value of x. State as an exact value. f(x)= e^x^... Determine the slope of the tangent at the indicated value of x f(x) = (x) cos^2 x, pie/4 determine the slope of the tangent to the curve x+(iny)^2 - e ^xy = 0 at the point (0,e)
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use