Question
determine the slope of the tangent for the following function. Then determine the equation of the tangent line at x=1
F(x) = x
F(x) = x^4
F(x) = x
F(x) = x^4
Answers
Anonymous
For F(x) = x, the first derivative - which is the slope of the line tangent to a curve - would be:
F'(x) = 1
For the second part, it doesn't matter what value x is, F'(x) is always 1.
For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:
F'(x) = 3x^3
For the second part, you just plug in 1 for x:
F'(x) = 3(1)^3 = 3
F'(x) = 1
For the second part, it doesn't matter what value x is, F'(x) is always 1.
For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:
F'(x) = 3x^3
For the second part, you just plug in 1 for x:
F'(x) = 3(1)^3 = 3
Anonymous
HOLD ON!!! MY BAD!
The second function's derivative is wrong. Brain fart on my part.
For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:
F'(x) = 4x^3
For the second part of the question, you just plug in 1 for x:
F'(x) = 4(1)^3 = 4
The second function's derivative is wrong. Brain fart on my part.
For F(x) = x^4, the first derivative - which is the slope of the line tangent to a curve - would be:
F'(x) = 4x^3
For the second part of the question, you just plug in 1 for x:
F'(x) = 4(1)^3 = 4