Question
A ball is thrown with a speed of 100m/s attains a height of 150m.Calculate <a>the time of flight <b>the angle of projection</b>
Answers
drwls
Time of flight:
That would be twice the time it takes the ball to fall H = 150 m, which is
t = 2*sqrt(2H/g) = 11.07 s
(You double the fall time to get the total time of flight)
Launch angle:
V*sinA/g = t/2 = 5.533 s
sin A = 0.5422
A = 32.8 degrees
Range:
(Vo^2/g)*sin(2A) = 930 m
Note: No human being can throw a ball that fast, or that far. It would be 224 miles per hour
That would be twice the time it takes the ball to fall H = 150 m, which is
t = 2*sqrt(2H/g) = 11.07 s
(You double the fall time to get the total time of flight)
Launch angle:
V*sinA/g = t/2 = 5.533 s
sin A = 0.5422
A = 32.8 degrees
Range:
(Vo^2/g)*sin(2A) = 930 m
Note: No human being can throw a ball that fast, or that far. It would be 224 miles per hour
Nonso
But they gave answers to b <a>15.49s <b>50.70degree </b>
drwls
Those are my final answers.
Nonso
Ok, tnx
Simeon E
Height of 100m and speed of 50ms-1?calcuate.the angle of projection?
saidu
a ball is thrown with a speed of 100m/s,attain a height of 150m,calculate the time of flight,angle of projection, and the range. take g to be 9.8m/s.
Odesola Kenneth
To find time of flight t=2u sin ₹/g
Anonymous
15.44sec
Anonymous
I need the procedure on how to solve the question
Oluwatunmise
NONSO should try to reexplain
mubaraq
Well