Asked by Jenetta
A ball is thrown with a speed of 19m/s and at an angle of 46 degrees. How high does it go above the cliff to the nearest tenth?
Answers
Answered by
bobpursley
PE gained=KE
mgh=1/2 m (19sin46)^2
solve for h, the height gained.
mgh=1/2 m (19sin46)^2
solve for h, the height gained.
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