Question
A ball is thrown with a speed of 19m/s and at an angle of 46 degrees. How high does it go above the cliff to the nearest tenth?
Answers
bobpursley
PE gained=KE
mgh=1/2 m (19sin46)^2
solve for h, the height gained.
mgh=1/2 m (19sin46)^2
solve for h, the height gained.