Asked by shai
Mr Dominguez is standing on a 40 ft ocean bluff near his home. He can see his two dogs on the beach below. If his line of sight is 6 ft above the ground and the angles of depression to his dogs are 34 degrees and 48 degrees, how far apart are the dogs to the nearest foot?
Answers
Answered by
Rohit
y = 46 ..
1st dog ... tan 34 = y/x ... x = 46/ tan 34 ... x = 68.198 feet
2nd dog .. tan 48 = y/x ... x = 46/ tan 48 ... x = 41.42 feet
68.198 - 41.42 = 26.8 feet ~ 27 feet << answer
1st dog ... tan 34 = y/x ... x = 46/ tan 34 ... x = 68.198 feet
2nd dog .. tan 48 = y/x ... x = 46/ tan 48 ... x = 41.42 feet
68.198 - 41.42 = 26.8 feet ~ 27 feet << answer
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