Asked by Stanley3000
Calculate the pH of a solution made by adding 3.50 g of lithium oxide (Li2O) to enough water to make 1.290 L of solution. (Kw = 1.0 10-14)
Answers
Answered by
DrBob222
..........Li2O + HOH ==> 2LiOH
1 mol Li2O produces 2 mols LiOH. How many moles Li2O do you have? I see mol = grams/molar mass
mol Li2O = 3.50 g Li2O/molar mass Li2O = ?
Then twice that gives moles LiOH produced.
M = mols LiOH/L LiOH.
M LiOH = moles OH^-; convert to H^+ by
H^+)(OH^-) = Kw ; then convert to pH.
pH = -log(H^+)
1 mol Li2O produces 2 mols LiOH. How many moles Li2O do you have? I see mol = grams/molar mass
mol Li2O = 3.50 g Li2O/molar mass Li2O = ?
Then twice that gives moles LiOH produced.
M = mols LiOH/L LiOH.
M LiOH = moles OH^-; convert to H^+ by
H^+)(OH^-) = Kw ; then convert to pH.
pH = -log(H^+)
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