Asked by frankscience
Calculate the pH of a solution of ammonium acetate (CH3COONH4) 0,85M knowing that for NH3 Kb = 1,79x10-5 and CH3COOH Ka = 1,76x10-5 and commented on the result obtained. Then calculate the percentage of acetic acid product at equilibrium
Answers
Answered by
DrBob222
(H^+) = sqrt(Kw/KaKb) and convert H^+ to pH.
ammonium acetate = NH4Ac
NH4Ac + HOH ==> NH4OH + HAc
Plug in H^+ to Ka expression for HAc and calculate HAc.
ammonium acetate = NH4Ac
NH4Ac + HOH ==> NH4OH + HAc
Plug in H^+ to Ka expression for HAc and calculate HAc.
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