32 inches?
What am I missing?
What does the length of the pipe have to do with it?
Suppose that 8 turns of a wire are wrapped around a pipe with a length of 60 inches and a circumference of 4 inches. What is the length of the wire
7 answers
think you mean "...8 turns of wire are..."
I guess you mean that the wire starts at one end of the pipe and ends up at the other end of the pipe.
So the wire has travelled 60 inches along the length of the pipe and 32 inches around the pipe. If you imagine the sides of the pipe unwound to form a big rectangle, you could also imagine that the wire would be sort of travelling a diagonal of the rectangle, i.e. you can use Pythagoras:
x^2 = 60^2 + 32^2
x^2 = 3600 + 1024
x^2 = 4624
x = sqrt(4624)
I guess you mean that the wire starts at one end of the pipe and ends up at the other end of the pipe.
So the wire has travelled 60 inches along the length of the pipe and 32 inches around the pipe. If you imagine the sides of the pipe unwound to form a big rectangle, you could also imagine that the wire would be sort of travelling a diagonal of the rectangle, i.e. you can use Pythagoras:
x^2 = 60^2 + 32^2
x^2 = 3600 + 1024
x^2 = 4624
x = sqrt(4624)
68
68
68 incheslong
32 inches
Suppose that 8 turns of a wire are wrapped around a pipe with a length of 60 inches and a circumference of 4 inches, so that the wire reaches from the bottom of the pipe to the top. What is the length of the wire? (Hint: Picture cutting the pipe along its length and pressing it flat.)
2 answers