Asked by brett
Phrank (36.4kg) runs at 2.2 m/s and jumps onto a large stationary skateboard (2.3kg) on which Phrancine (22.7kg) is sitting. After the collision, Phrank, Phrancine, and the skateboard move at 1.3 m/s. Find the momentum before and after the collision along with the percent difference.
Answers
Answered by
drwls
Before hopping on,
Momentum = 36.4* 2.2 = 80.08 kg m/s
After hopping on,
Momentum = (36.4 + 2.3 + 22.7)*1.3 = 79.82 m/s
Since there are only two significant figures in your numbers, the 0.3% computed decrease in momentum is not significant. No momentum should have been lost at all. There is a law that says there should be no total momentum decrease if there are no "outside forces" , but friction while getting on may have reduced it slightly.
Momentum = 36.4* 2.2 = 80.08 kg m/s
After hopping on,
Momentum = (36.4 + 2.3 + 22.7)*1.3 = 79.82 m/s
Since there are only two significant figures in your numbers, the 0.3% computed decrease in momentum is not significant. No momentum should have been lost at all. There is a law that says there should be no total momentum decrease if there are no "outside forces" , but friction while getting on may have reduced it slightly.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.