Asked by Scooby10
The area of a floating circular oil spill in the ocean is increasing at a rate of 96pi square meters per second. When the area of the spill is 1000pi how fast is the radius increasing in meters per second.
Answers
Answered by
Reiny
Area = πr^2
d(area)/dt = 2πr dr/dt
when area = 1000π
πr^2 = 1000π
r^2=1000
r = √1000 = 10√10
96π = 2π(10√10)dr/dt
dr/dt = 96/(20√10) or 24/(5√10) or 12√10/25
= appr. 1.52
d(area)/dt = 2πr dr/dt
when area = 1000π
πr^2 = 1000π
r^2=1000
r = √1000 = 10√10
96π = 2π(10√10)dr/dt
dr/dt = 96/(20√10) or 24/(5√10) or 12√10/25
= appr. 1.52
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