Asked by Lucina
The circular area of the drum is (9x^2+30x+25)pi. What is the smallest diameter it can have?
(9x^2+30x+25)
(3x+15) (3x+15)
3(x+5) 3(x+5)
9(x+5)
9x+45 <--------
(9x^2+30x+25)
(3x+15) (3x+15)
3(x+5) 3(x+5)
9(x+5)
9x+45 <--------
Answers
Answered by
bobpursley
(9x^2+30x+25)PI
(3x+5) (3x+5)PI
(3x+5)^2 * PI=area
but area =PI r^2
r^2=(3x+5)^2
r= 3x+5
D=2r=6x+10
(3x+5) (3x+5)PI
(3x+5)^2 * PI=area
but area =PI r^2
r^2=(3x+5)^2
r= 3x+5
D=2r=6x+10
Answered by
Lucina
Thank you
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