Asked by Karie

Calculate the pH of the following buffer solutions:
a) a solution made by dissolving 2.733g KH2PO4 and 4.508g K2HPO4 in water to give 250 ml of solution.

b)a solution made by mixing 35.00 ml 0.24 M C6H5NH2 with 15.00 ml 0.19 M C6H5NH3CL. The base dissociation constant Kb is 4.00 X 10^-10 for C6H5NH2. Assume that the final volume is the sume of the volumes of the two solutions that are mixed.
Answered by DrBob222
Use the Henderson-Hasselbalch equation. If you get stuck explain what it is you don't understand.
Answered by Karie
I don't understand where to start. Do i turn the grams given in part a) to moles first? then i am not sure what to do
Answered by DrBob222
Yes, convert g to moles. Look up the Ka value for the acid and convert that to pKa, then plug into the HH and calculate pH.
Answered by Karie
how would you do part b?
Answered by laura
you have 20 ml of 0.1 M aqueous solution of the weak base (CH3)N (Kb = 7.4 x 10^-5). This solution will be titrated with 0.1 M HCl.

how many ml of acid must be added to reach the equivalence point?
Answered by yes
a) 7.432
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