Asked by Jane
The area of a rectangle is 6n(to the power of 2) + n - 2. What is the expression that represents the perimeter of the rectangle?
Answers
Answered by
bobpursley
area= LW=6n^2+n-2=(3n-2)(n+1)
perimeter then is 2L+2W=2(l+w)=2(3n-2+n+1)
= 2(4n-1)
perimeter then is 2L+2W=2(l+w)=2(3n-2+n+1)
= 2(4n-1)
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