Asked by Lezah
A plane is flying due south at a speed of 300 mph. The wind is blowing from the west at a speed of 40 mph. Find the resultant speed of the plane and the direction of the plane
Answers
Answered by
Henry
V = 300 mi/h @ 270Deg + 40 mi/h @ 0Deg.
X = 40 mi/h.
Y = -300 mi/h.
tanA = Y/X = -300 / 40 = -7.500.
A = -82.4 Deg.,CW.
A = -82.4 + 360 = 277.6 Deg, CCW.
Vp = X/cosA = 40 / cos277.6 = 303 mi/h
@ 277.6 Deg.
X = 40 mi/h.
Y = -300 mi/h.
tanA = Y/X = -300 / 40 = -7.500.
A = -82.4 Deg.,CW.
A = -82.4 + 360 = 277.6 Deg, CCW.
Vp = X/cosA = 40 / cos277.6 = 303 mi/h
@ 277.6 Deg.
Answered by
Alex Jones
X=68+1
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