Question

A plane is flying due South (270º) at 474.8 km/h. A wind blows from West to East (0°) at 46 km/h.
Find the direction of the plane's travel. Report your answer in degrees from 0° as a reference.
46 km/h [Horizontal]
--->
\. |
.\.|
..\v -474.8 km/h [Vertical]

We're trying to find the angle in the top left corner of the triangle above. We already have the lengths of the two legs, so we'd do this using tan.

Tan(x) = Opposite/Adjacent
Tan(x) = (-474.8)/(46) = -10.3217
x = Tan-1(-10.3217)
x = -84.47 degrees

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