Asked by victor.m
Evaluate using partial fractions
x^4 - 16/x^3 - 8
x^4 - 16/x^3 - 8
Answers
Answered by
Reiny
did you mean (x^4 - 16)/(x^3 - 8) ? , then
= (x+2)(x-2)/((x-2)(x^2 + 2x + 4))
= (x+2)/(x^2 + 2x + 4) , x ≠ 2
In the process of partial fractions, the denominator usually factors into rational factors.
Your denominator does not factor.
So unless we use complex number factors, this does not fit into the category of "partial fractions"
= (x+2)(x-2)/((x-2)(x^2 + 2x + 4))
= (x+2)/(x^2 + 2x + 4) , x ≠ 2
In the process of partial fractions, the denominator usually factors into rational factors.
Your denominator does not factor.
So unless we use complex number factors, this does not fit into the category of "partial fractions"
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