resolve the partial fraction: x^3+6/x^2x+6.plz explain thanks

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how to you use partial fractions to compute the integral of ax/((x^2)-bx)dx?

Resolve in partial fractions (x+6)/((x^2+1)(x-2)^2) Using let x = ...

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Resolve this into partial fraction:x^2+x+4/(1-x)(x^2+1)

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