delta T = dT = Kf*m
Substitute Kf and m and solve for dT. Then subtract from the normal freezing point to find the new freezing point.
Benzene freezes at 5.45oC. The Kf for benzene is - 5.07 oC/m. What would be the freezing point of a 0.210m solution of octane in benzene
a) 1.06oC
b) 4.39oC
c) 6.51oC
d) 10.52oC
e) 5.80oC
2 answers
answer is b
1 answer