Asked by Kyra
Liquid nitrogen freezes at -346 degrees F and boils -321 F. Janice gradually heats frozen nitrogen 1 1/2 degrees several times over an hour.
1)Define variables for the number of times Janice increases the temperature and the temperature of the liquid nitrogen after the temperature increases.
- I have N= number of times she tries
T-temperature
2)Write an equation that shows the relationship between the 2 variables.
???? Not sure how to do this. Would it be -346 - 1 1/2N=T
1)Define variables for the number of times Janice increases the temperature and the temperature of the liquid nitrogen after the temperature increases.
- I have N= number of times she tries
T-temperature
2)Write an equation that shows the relationship between the 2 variables.
???? Not sure how to do this. Would it be -346 - 1 1/2N=T
Answers
Answered by
Mia
Because -321F is more than -346F you would add to -346F instead of subtract from it.
Subtracting would make the temperature lower. Remember the closer a negative number is to zero the higher it is.
Subtracting would make the temperature lower. Remember the closer a negative number is to zero the higher it is.
Answered by
Kyra
Ok. So if I had to use the equation to calculate the temperature if it is increased 3 times. I would do
-346 + 1 1/2(n)=T
-346 + 1 1/2(3)=T
-346 + 4 1/2=-341 1/2
Is that right?
Thanks
-346 + 1 1/2(n)=T
-346 + 1 1/2(3)=T
-346 + 4 1/2=-341 1/2
Is that right?
Thanks
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