Asked by Casey
Suppose the revenue from producing and selling x units of a given product is given by R(x)=10x-0.02x^2
a) Find the number of units produced if the revenue is $800.
I really need help with this, I don't know what to do?
a) Find the number of units produced if the revenue is $800.
I really need help with this, I don't know what to do?
Answers
Answered by
Reiny
just set R(x) = 800
800 = 10x - .02x^2
.02x^2 - 10x + 800 = 0
using the quad formula
x = (10 ± √36)/.04 , ahhh it would have factored
= (10 ± 6)/.04
= 400 or 100 units
800 = 10x - .02x^2
.02x^2 - 10x + 800 = 0
using the quad formula
x = (10 ± √36)/.04 , ahhh it would have factored
= (10 ± 6)/.04
= 400 or 100 units
Answered by
Casey
The answer that I have to this question is 1000 units, I am confused.
Answered by
Reiny
sub in your answer
R(1000) = 10(1000) - .02(1000)^2 = -10 000
my answers
R(400) = 10(400) - .02(400)^2 = 800
R(100) = 10(100) - .02(100)^2 = 800
Why are you confused?
how did you possible get 1000?
R(1000) = 10(1000) - .02(1000)^2 = -10 000
my answers
R(400) = 10(400) - .02(400)^2 = 800
R(100) = 10(100) - .02(100)^2 = 800
Why are you confused?
how did you possible get 1000?
Answered by
Casey
I know I am getting the answer as you did, but the solution that I have with the question that says 1000
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