Asked by jordan
Maximizing Revenue Suppose the quantity demanded per week of a certain dress is related to the unit price p by the demand equation
p= sqrt(400-x)
where p is in dollars and x is the number of dresses made. To maximize the revenue, how many dresses should be made and sold each week? (Round your answer to the nearest whole number.) Hint:
R(x) = px.
____ dress?
p= sqrt(400-x)
where p is in dollars and x is the number of dresses made. To maximize the revenue, how many dresses should be made and sold each week? (Round your answer to the nearest whole number.) Hint:
R(x) = px.
____ dress?
Answers
Answered by
oobleck
c'mon
r = x√(400-x)
r' = (800-3x)/(2√(400-x))
r'=0 at x = 800/3
r = x√(400-x)
r' = (800-3x)/(2√(400-x))
r'=0 at x = 800/3
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