Asked by anonymous
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log (small 2)(x+1)-log (small 2)x=log(small 2) 7
log (small 2)(x+1)-log (small 2)x=log(small 2) 7
Answers
Answered by
Steve
log_2(x+1) - log_2(x) = log_2(7)
log_2((x+1)/x) = log_2(7)
(x+1)/x = 7
x = 1/6
log_2((x+1)/x) = log_2(7)
(x+1)/x = 7
x = 1/6
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