Asked by Tiara
wat is the indefinite integral of dx/x^2? Is it 2 ln /x/ + C?
Answers
Answered by
Damon
hint
d/dx (1/x) = [(x*0) - (1*1) ]/x^2 =-1/x^2
d/dx (1/x) = [(x*0) - (1*1) ]/x^2 =-1/x^2
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