Asked by Matthew
solve for x
2^x=0.125
5^2x=39
13^x=27
2^x=0.125
5^2x=39
13^x=27
Answers
Answered by
Anonymous
2 ^ x = 0.125
Take the logarithm to the base 2 of both sides:
log ( a ^ n ) = n * log ( a )
log( base 2 ) [ 2 ^ x ] = log( base 2 ) ( 2 ) * x = 1 * x = x
Becouse: log( base 2 ) ( 2 )
0.125 = 1 / 8 = 1 / 2 ^ 3 = 2 ^ ( - 3 )
log( base 2 ) [ 2 ^ ( - 3 ) ] = - 3
log( base 2 ) [ 2 ^ x ] = - 3
5 ^ ( 2 x ) = 39
2 x * log ( 5 ) = log ( 39 ) Divide both sides by ] 2 * log ( 5 ) ]
x = log ( 39 ) / [ 2 log ( 5 ) ]
x = 1.13815
13 ^ x = 27
x * log ( 13 ) = log ( 27 ) Divide both sides by log ( 13 )
x = log ( 27 ) / log ( 13 )
x = 1.28495
Take the logarithm to the base 2 of both sides:
log ( a ^ n ) = n * log ( a )
log( base 2 ) [ 2 ^ x ] = log( base 2 ) ( 2 ) * x = 1 * x = x
Becouse: log( base 2 ) ( 2 )
0.125 = 1 / 8 = 1 / 2 ^ 3 = 2 ^ ( - 3 )
log( base 2 ) [ 2 ^ ( - 3 ) ] = - 3
log( base 2 ) [ 2 ^ x ] = - 3
5 ^ ( 2 x ) = 39
2 x * log ( 5 ) = log ( 39 ) Divide both sides by ] 2 * log ( 5 ) ]
x = log ( 39 ) / [ 2 log ( 5 ) ]
x = 1.13815
13 ^ x = 27
x * log ( 13 ) = log ( 27 ) Divide both sides by log ( 13 )
x = log ( 27 ) / log ( 13 )
x = 1.28495
Answered by
Anonymous
log( base 2 ) [ 2 ^ ( - 3 ) ] = - 3
x = -3
x = -3
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