Asked by Maria Ellah
A force of 250 N is just sufficient to start a 50 kg steel trunk moving across a wooden floor. Find the coefficient of static friction.
Answers
Answered by
drwls
Use what you have learned from my previous three answers to attempt this yourself.
Answered by
Maria Ellah
Sir, static and kinetic are different isn't it?
Answered by
drwls
Yes they are different.
250 N = M*g*Us = 490N * Us
Solve for Us, the static friction coefficient.
Us tells you how big the applied force must be to make it move.
250 N = M*g*Us = 490N * Us
Solve for Us, the static friction coefficient.
Us tells you how big the applied force must be to make it move.
Answered by
Maria Ellah
Sir, gonna have some favor. What will be the formula to use?
Answered by
drwls
I already wrote and substituted numbers in the formula above.
(Force required to move) = (Weight)*Us
Us = (Force required to move)/(Weight)
= 250/490
This formula applies on level horizontal ground only
(Force required to move) = (Weight)*Us
Us = (Force required to move)/(Weight)
= 250/490
This formula applies on level horizontal ground only
Answered by
Maria Ellah
thanks sir. that's what i'm gonna ask. for horizontal ground only. Godspeed! :)
Answered by
kh
aforce of 200N is just sufficient to start a 50-kg steel trunk moving across awooden floor. find the coefficient of static friction
Answered by
Rhoda
aforce of 200N is just sufficient to start a 50-kg steel trunk moving across awooden floor. find the coefficient of static friction
Answered by
Vincent
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