Asked by Maria Ellah

A force of 1000 N is applied to a 1200 kg car. If the coefficient of friction is 0.04, what is the car's acceleration?
Answered by drwls
a = Fnet/m

The net force is
Fnet = 1000 - M*g*Uk
= 1000 - 470.4 = 529.6 N

a = 529.6/1200 = 0.441 m/s^2
Answered by Maria Ellah
thank you!
Answered by jocynt
how did you cope in this answer what is the formula and solution?
Answered by Shraddhanjali
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