Asked by Steven
What is the simplified version of
(2x^(-3)y^(2))^(-2)
and
(z^4)/(2z^3)
Thanks!
(2x^(-3)y^(2))^(-2)
and
(z^4)/(2z^3)
Thanks!
Answers
Answered by
Jai
#1
(2x^(-3)y^(2))^(-2)
(2)^(-2) * x^(-3*(-2)) * y^(2*(-2))
(1/4) * x^(6) * (1/y^4)
(x^6)/(4y^4)
#2
(z^4)/(2z^3)
z/2
hope this helps~ :)
(2x^(-3)y^(2))^(-2)
(2)^(-2) * x^(-3*(-2)) * y^(2*(-2))
(1/4) * x^(6) * (1/y^4)
(x^6)/(4y^4)
#2
(z^4)/(2z^3)
z/2
hope this helps~ :)
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