A water pistol aimed horizontally projects a stream of water with an initial speed of 5.65 m/s. How far does it travel before dropping a vertical distance of 1.50 cm?

Answer 1

Multiply the horizontal speed component (which remains constant) by the time T that it takes the water to fall 1.50 cm.

(g/2) T^2 = 0.015 m
T = sqrt(0.03/g) = 0.0553 s

X = 0.313 m not very far!