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Marie shoots an arrow vertically upward at a sandhill crane. If the arrow travels to a maximum height of 99.5 meters, calculate...Asked by qwertzuiop
Marie shoots an arrow vertically upward at a sandhill crane. If the arrow travels to a maximum height of 99.5 meters, calculate how fast it was shot.
And, for how much time was Marie's arrow in the air?
And, for how much time was Marie's arrow in the air?
Answers
Answered by
Damon
v = Vi - 9.8 t
0 = Vi - 9.8 t
Vi = 9.8 t
99.5 = Vi t -4.9 t^2
99.5 = 9.8 t^2 - 4.9 t^2 = 4.9 t^2
t = 4.5 seconds to top
so
Vi = 9.8 * 4.5 = 44.2 m/s
You could also do this by conservation of energy
(1/2) m Vi^2 = m g h
so
Vi = sqrt (2*9.8*99.5)
= 44.2 m/s
0 = Vi - 9.8 t
Vi = 9.8 t
99.5 = Vi t -4.9 t^2
99.5 = 9.8 t^2 - 4.9 t^2 = 4.9 t^2
t = 4.5 seconds to top
so
Vi = 9.8 * 4.5 = 44.2 m/s
You could also do this by conservation of energy
(1/2) m Vi^2 = m g h
so
Vi = sqrt (2*9.8*99.5)
= 44.2 m/s