Asked by qwertzuiop
Marie shoots an arrow vertically upward at a sandhill crane (she misses the crane, so you PETA members can relax). If the arrow travels to a maximum height of 99.5 meters, calculate how fast it was shot.
And, for how much time was Marie's arrow in the air?
And, for how much time was Marie's arrow in the air?
Answers
Answered by
Henry
a. Vf^2 = Vo^2 + 2g*d,
Vo^2 = Vf^2 - 2g*d,
Vo^2 = 0 - (-19.6)99.5 = 1950,
Vo = 44.2 m/s.
b. Tr=Tf= (Vf-Vo)/g=(0-44.2)/-9.8=2.26s
= Rise time = Fall time.
Tr + Tf = 2.26 + 2.26 = 4.52 s. = Time in air.
Vo^2 = Vf^2 - 2g*d,
Vo^2 = 0 - (-19.6)99.5 = 1950,
Vo = 44.2 m/s.
b. Tr=Tf= (Vf-Vo)/g=(0-44.2)/-9.8=2.26s
= Rise time = Fall time.
Tr + Tf = 2.26 + 2.26 = 4.52 s. = Time in air.