A girl shoots an arrow from the top of a cliff. The arrow is initially at a point 20 meters above the level field below. The arrow is shot at an angle of 30 degrees above the horizontal with a speed of 39.2m/s. How far out from the base of the cliff will the arrow land?

3 answers

You need to first find the time in the air, from the vertical flight equation. You can figure the initial vertical velocity from the angle.

hcliff=vi*time -1/2 g time^2
solve for time.

Then, use that time for the horizontal equation..

d=vhorizontal*tiem

i tried that. it doesnt work

nvm it works. thanksssssss