Asked by Tor
An object has a weight of 0.838 N. It is suspended from a scale, which reads 0.705 N when the piece is submerged in water. What are the volume and density of the piece of metal?
Answers
Answered by
drwls
The buoyancy force is 0.838 - 0.705 = 0.133 N
Let D be the density and V be the volume
D*V*g = 0.838 newtons
(1000 kg/m^3)*V*g = 0.133 newtons
(That came from Archimedes principle)
D = 6300 kg/m^3 (or 6.3 g/cm^3)
V = 0.838/(6300 g) = 1.357*10^-5 m^3
= 13.57 cm^3
Let D be the density and V be the volume
D*V*g = 0.838 newtons
(1000 kg/m^3)*V*g = 0.133 newtons
(That came from Archimedes principle)
D = 6300 kg/m^3 (or 6.3 g/cm^3)
V = 0.838/(6300 g) = 1.357*10^-5 m^3
= 13.57 cm^3
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