Question

Mary walked north from her home to Sheila's home, which is 4.0 kilometers away. Then she turned right and walked another 3.0 kilometers to the supermarket, which is 5.0 kilometers from her own home. She walked the total distance in 1.5 hours. What were her average speed and average velocity?

Answer 1

1. Speed = d/t = (4+3) / 1.5=4.66 km/h.

2. tanA = 4/3 = 1.333,
A = 53.12 Deg.
D = X/cosA = 3/cos53.12 = 5 km @ 53.12 Deg.
V = 5 / 1.5 = 3.33 km/h @ 53 Deg.