Asked by faith
an object of mass 1kg falls a distance 5m on a horizontal surface and bounce to a vertical height of 2m.calculate the change in momentum
Answers
Answered by
Damon
v down = sqrt (2 g h) = sqrt (2*9.8*5)
= 9.9 m/s
v up = sqrt (2 * 9.8*2)
= 6.26
change in momentu = m delta v = 1(9.9+6.26)
= 16.2 kg m/s
= 9.9 m/s
v up = sqrt (2 * 9.8*2)
= 6.26
change in momentu = m delta v = 1(9.9+6.26)
= 16.2 kg m/s
Answered by
Joyce
I don't understand
Answered by
Sagacious
Nice one đ
Answered by
Sagacious
Joyce you recall
V² = U² + 2gh
But here u = 0
You now have
V = â2gh
So you use it to find the first and second velocity
V² = U² + 2gh
But here u = 0
You now have
V = â2gh
So you use it to find the first and second velocity
Answered by
Anthony
I didn't understand
Answered by
Musa
Physical address
Answered by
Felicia
How did you get v down
Answered by
Emmanuel
It from the equation đ¤đ¤
Answered by
Tammy
I really understand. Thank you â¤ď¸â¤ď¸
Answered by
Sandra
I don't understand
Answered by
Anonymous
I don't understand
Answered by
Nathaniel
I think Damon is correct
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.