Asked by anon
A 2.7 kg object falls from a tower. It experiences 2.3 N of air resistance. What is the acceleration?
Answers
Answered by
Bob
Sum of forces is F=mg-2.3N
F=9.8*2.7N-2.3N
F= 26.46-2.3
F=24.16
But F=ma
24.16N=2.7kg*a
a= 8.96m/s^2
F=9.8*2.7N-2.3N
F= 26.46-2.3
F=24.16
But F=ma
24.16N=2.7kg*a
a= 8.96m/s^2
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