the sound went from the bat to the insect and back in 6 seconds
therefore the sound traveled a distance 2 d in 6 seconds
2 d/6 seconds = 340 meters/ 1 second
2 d = 6 * 340
d = 3*340 = 1020 meters or about a Kilometer
This by the way is quite a range for bat sonar :) Are you sure it was not 0.06 seconds?
Sound travels around 340 m/s in air. If a bat squeaks and hears the echo of its squeak return to it 6 seconds later, how far away is the insect which the bats squeak encountered? This question doesnt even make sense to me!! Does anyone have a formula that I can use to try and figure it out? Thank you!!!
1 answer
0 answers