Question
A man standing 2040m from the foot of a high building claps his hands and hears the echo. 4 second later (speed of sound in air at 0 ^ 0 * c is 331m / s )
a. What is the velocity of the sound in the air?
b. What is the temperature at that place?
a. What is the velocity of the sound in the air?
b. What is the temperature at that place?
Answers
Bot
a. We can use the formula:
distance = speed x time
The man claps his hands and hears the echo 4 seconds later. This means the sound had to travel a total of 4080 meters (2040m to the building and then back to the man). So:
4080m = speed x 4s
Speed = 1020 m/s
Therefore, the velocity of the sound in the air is 1020 m/s.
b. The speed of sound in air depends on the temperature of the air. At 0 ^ 0 *C, the speed of sound in air is 331 m/s. We can use the formula:
speed = 331 m/s x sqrt(1 + (T/273))
where T is the temperature in degrees Celsius.
We can rearrange this formula to solve for T:
T = (speed/331)^2 x 273 - 273
Plugging in the speed we found above, we get:
T = ((1020 m/s)/331)^2 x 273 - 273
T ≈ 39°C
Therefore, the temperature at that place is approximately 39°C.
distance = speed x time
The man claps his hands and hears the echo 4 seconds later. This means the sound had to travel a total of 4080 meters (2040m to the building and then back to the man). So:
4080m = speed x 4s
Speed = 1020 m/s
Therefore, the velocity of the sound in the air is 1020 m/s.
b. The speed of sound in air depends on the temperature of the air. At 0 ^ 0 *C, the speed of sound in air is 331 m/s. We can use the formula:
speed = 331 m/s x sqrt(1 + (T/273))
where T is the temperature in degrees Celsius.
We can rearrange this formula to solve for T:
T = (speed/331)^2 x 273 - 273
Plugging in the speed we found above, we get:
T = ((1020 m/s)/331)^2 x 273 - 273
T ≈ 39°C
Therefore, the temperature at that place is approximately 39°C.