Question

A runner dashes from the starting line (x = 0) to a point 91 m away and then turns around and runs to a point 30 m away from the starting point in 25 seconds. To the nearest tenth of a m/s what is the average speed?
V = d/t = (91 + (91-30)) / 25 =
6.08

Related Questions

1 A runner dashes from the starting line (x = 0) to a point 130 m away and then turns around and r... A runner dashes from the starting line (x = 0) to a point 80 m away and then turns around and runs t... A runner dashes from the starting line (x=0) to a point 134 m away and then turns around and runs to...