Question
A piece of metal with a mass of 5.50 grams changed in temperature from 25.0 to 55.0C when 21.3 joules was absorbed. The specific heat of the metal is
a. 0.256
b. 0.129
c. 3.91
d. 7.75
e. 0.710J g-1 oC-1
desperately need help!
a. 0.256
b. 0.129
c. 3.91
d. 7.75
e. 0.710J g-1 oC-1
desperately need help!
Answers
q = mass metal x specific heat metal x delta T.
q = 21.3 J.
Substitute and solve for specific heat.
q = 21.3 J.
Substitute and solve for specific heat.
is it b?
yes
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