Asked by Jenna

A piece of metal with a mass of 5.50 grams changed in temperature from 25.0 to 55.0C when 21.3 joules was absorbed. The specific heat of the metal is
a. 0.256
b. 0.129
c. 3.91
d. 7.75
e. 0.710J g-1 oC-1

desperately need help!
Answered by DrBob222
q = mass metal x specific heat metal x delta T.
q = 21.3 J.

Substitute and solve for specific heat.
Answered by timmy
is it b?
Answered by DrBob222
yes
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