Asked by Momo

A piece of metal of mass 20.0g @ 100°C is placed in a calorimeter containing 50.7g of water at 22.0°C. The final temperature of the mixture is 25.7°C. What is the specific heat capacity of the metal? Assume that no energy leaves to the surroundings.

Not sure how to work this problem out. Help please? Thank u!

Answers

Answered by DrBob222
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
You have all except specific heat metal. Solve for that.
Answered by Anonymous
If 46.1 g Cu at 11.6 C is placed in 85.0 g H2O at 72.4 C, what is the final temperature of the mixture? (specific heat capacities: Cu: 0.385 J/gK Water: 4.184 J/gK)?
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