Asked by Anonymous

A rock concert, 5.17 10-6 watts/cm2
D = dB

Answers

Answered by drwls
If the sound intensity is 5.17*10^-6 W/cm^2, the dB level is

10Log(10)[5.17*10^-6/10^-16]
10Log(10)[5.17*10^10] = 107.1 dB

Ref:
http://hyperphysics.phy-astr.gsu.edu/hbase/sound/intens.html#c1
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