Asked by Dee

A 10 g bullet is fired into, and embeds itself in, a 2 kg block attached to a spring with a force constant of 19.6 n/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Use conservation of momentum.

Answers

Answered by drwls
Conservation of momentum tells you the velocity V' of the block and embedded bullet before the spring gets compressed.

0.010 kg*300 m/s = V' * (2.01 kg)
Solve for V'.

Energy is conserved during spring compression.

(1/2) k X^2 = (1/2) (M+m) V'^2

k is the spring force constant. M is block mass. m is bullet mass.

Solve for spring compression X
Answered by LazyStudent
After the bullet embeds inside the block, is it going to be m1+m2?
Answered by LazyStudent
Now I get it, thanks.
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