Asked by Resha
The perimeter of a rectangle is 110cm. The length is 1cm more than twice the width. Write 2 equations that would be used to solve the system.
Answers
Answered by
Henry
Eq1: 2L + 2W = 110.
Eq2: L = 2W+1
2(2W+1) + 2W = 110.
Eq2: L = 2W+1
2(2W+1) + 2W = 110.
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