Asked by kyle
A woman pushes a crate along the floor of a warehouse with a force of 31.9 N directed downward at an angle of 23.6° from the horizontal. If the crate has a mass of 11.9 kg and the coefficient of friction is 0.0975, find...
(a) the force of friction
b. (b) theacceleration
(a) the force of friction
b. (b) theacceleration
Answers
Answered by
drwls
(a) (0.0975)*(M*g + 31.9 sin23.6) = 12.62 N
(b) [31.9 cos23.6 - 12.62]/M = 1.40 m/s^2
(b) [31.9 cos23.6 - 12.62]/M = 1.40 m/s^2
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