Asked by Carl
Solve by substitution:
4x-12y =5
-x + 3y = -1
4x-12y =5
-x + 3y = -1
Answers
Answered by
Carol
4x-12y=5
4x+-12y+12y=5
4x/4=5/4
x=5/4 =1 1/4
4x+-12y=5
-4x+-12y=5
-12y/-12=5/-12
y=-5/12
-x+3y=-1
-x+3y-3y=-1
-x/-1=-1/-1
x=1
-x+3y=-1
-x+x+3y--1
3y/3=-1/3
y= -1/3
4x+-12y+12y=5
4x/4=5/4
x=5/4 =1 1/4
4x+-12y=5
-4x+-12y=5
-12y/-12=5/-12
y=-5/12
-x+3y=-1
-x+3y-3y=-1
-x/-1=-1/-1
x=1
-x+3y=-1
-x+x+3y--1
3y/3=-1/3
y= -1/3
Answered by
Carl
Carol! Thank you so much! I am to solve by substitution. I am a bit confused as to now having two separate y and x components, rather than one set of x and y/ If you have time, Please help me to understand/ Thank you. Carl
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